scalbn, scalbnf, scalbnl, scalbln, scalblnf, scalblnl
Header: <math.h>
1-3,5-7) Multiplies a floating-point value arg by FLT_RADIX raised to power exp .
# Declarations
float scalbnf( float arg, int exp );
(since C99)
double scalbn( double arg, int exp );
(since C99)
long double scalbnl( long double arg, int exp );
(since C99)
#define scalbn( arg, exp )
(since C99)
float scalblnf( float arg, long exp );
(since C99)
double scalbln( double arg, long exp );
(since C99)
long double scalblnl( long double arg, long exp );
(since C99)
#define scalbln( arg, exp )
(since C99)
# Parameters
arg: floating-point valueexp: integer value
# Return value
If no errors occur, arg multiplied by FLT_RADIX to the power of exp (arg×FLT_RADIXexp) is returned.
# Notes
On binary systems (where FLT_RADIX is 2), scalbn is equivalent to ldexp .
Although scalbn and scalbln are specified to perform the operation efficiently, on many implementations they are less efficient than multiplication or division by a power of two using arithmetic operators.
The scalbln function is provided because the factor required to scale from the smallest positive floating-point value to the largest finite one may be greater than 32767, the standard-guaranteed INT_MAX . In particular, for the 80-bit long double, the factor is 32828.
# Example
#include <errno.h>
#include <fenv.h>
#include <float.h>
#include <math.h>
#include <stdio.h>
// #pragma STDC FENV_ACCESS ON
int main(void)
{
printf("scalbn(7, -4) = %f\n", scalbn(7, -4));
printf("scalbn(1, -1074) = %g (minimum positive subnormal double)\n",
scalbn(1, -1074));
printf("scalbn(nextafter(1,0), 1024) = %g (largest finite double)\n",
scalbn(nextafter(1,0), 1024));
// special values
printf("scalbn(-0, 10) = %f\n", scalbn(-0.0, 10));
printf("scalbn(-Inf, -1) = %f\n", scalbn(-INFINITY, -1));
// error handling
errno = 0; feclearexcept(FE_ALL_EXCEPT);
printf("scalbn(1, 1024) = %f\n", scalbn(1, 1024));
if (errno == ERANGE)
perror(" errno == ERANGE");
if (fetestexcept(FE_OVERFLOW))
puts(" FE_OVERFLOW raised");
}